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Elections in Wisconsin |
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The 1848 United States presidential election in Wisconsin was held on November 7, 1848, as part of the 1848 United States presidential election. It was the first presidential election held in Wisconsin since its admission to the Union on May 29, earlier the same year. Democratic candidate Lewis Cass won the state with 38% of the vote, carrying the state's 4 electoral votes.
With 26.6% of the popular vote, Wisconsin would prove to be Van Buren's third strongest state after Vermont and Massachusetts.[1]
The 1848 election began a trend in Wisconsin where the state would vote the same as neighboring Iowa, as the two states have voted in lockstep with each other on all but 6 occasions - 1892, 1924, 1940, 1976, 2004, and 2020. This was the last time until 1988 that Wisconsin would back a losing Democrat in a presidential election.
Results
1848 United States presidential election in Wisconsin[2] | ||||||||
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Party | Candidate | Running mate | Popular vote | Electoral vote | ||||
Count | % | Count | % | |||||
Democratic | Lewis Cass of Michigan | William O. Butler of Kentucky | 15,001 | 38.30% | 4 | 100.00% | ||
Whig | Zachary Taylor of Louisiana | Millard Fillmore of New York | 13,747 | 35.10% | 0 | 0.00% | ||
Free Soil | Martin Van Buren of New York | Charles Francis Adams, Sr. of Massachusetts | 10,418 | 26.60% | 0 | 0.00% | ||
Total | 39,166 | 100.00% | 4 | 100.00% |
See also
References
- ↑ "1848 Presidential Election Statistics". Dave Leip’s Atlas of U.S. Presidential Elections. Retrieved March 5, 2018.
- ↑ "1848 Presidential General Election Results - Wisconsin". Retrieved May 10, 2016.